F(x+2)=2x^2-x+3

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Solution for F(x+2)=2x^2-x+3 equation: 



(F+2)=2F^2-F+3

We move all terms to the left:

(F+2)-(2F^2-F+3)=0

We get rid of parentheses

-2F^2+F+F+2-3=0

We add all the numbers together, and all the variables

-2F^2+2F-1=0

a = -2; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-2)·(-1)
Δ = -4
Delta is less than zero, so there is no solution for the equation

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